Thank you for reporting, we will resolve it shortly
Q.
What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?
AIPMTAIPMT 1989Some Basic Concepts of Chemistry
Solution:
$\underset{(12 \times2 +4)}{C _{2} H _{4}}+\underset{96\,kg}{3 O _{2}} \rightarrow 2 CO _{2}+2 H _{2}$
$=28\, kg$
$\because$ Weight of oxygen required for the Complete combustion of $28\, kg$ ethylene $=96\, kg$
$\because$ Weight of oxygen required for the combustion of $2.8\, kg$ ethylene.
$=\frac{96 \times 2.8}{28}=9.6\, kg$