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Q. What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

AIPMTAIPMT 1989Some Basic Concepts of Chemistry

Solution:

$\underset{(12 \times2 +4)}{C _{2} H _{4}}+\underset{96\,kg}{3 O _{2}} \rightarrow 2 CO _{2}+2 H _{2}$
$=28\, kg$
$\because$ Weight of oxygen required for the Complete combustion of $28\, kg$ ethylene $=96\, kg$
$\because$ Weight of oxygen required for the combustion of $2.8\, kg$ ethylene.
$=\frac{96 \times 2.8}{28}=9.6\, kg$