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  4. What is the weight (in gram) of Na 2 CO 3 (molar mass =106 ) present in 250 mL of its 0.2 M solution?

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Q. What is the weight (in gram) of $Na _{2} CO _{3}$ (molar mass $=106$ ) present in $250 \,mL$ of its $0.2\, M$ solution?

TS EAMCET 2015

Solution:

Molarity

$=\frac{\text { Weight of solute }}{\text { Molecular weight of solute }} \times \frac{1000}{\text { volume(in mL) }}$

$0.2=\frac{\text { Weight of solute }}{106} \times \frac{1000}{250}$

$\therefore $ Weight of solute $=\frac{0.2 \times 106 \times 250}{1000}=5.3 \,gm$