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  4. What is the wave number of 4th line in Balmer series of hydrogen spectrum? (R=1,09,677 cm-1)

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Q. What is the wave number of 4th line in Balmer series of hydrogen spectrum? $ (R=1,09,677\,c{{m}^{-1}}) $

EAMCETEAMCET 2007

Solution:

$ \bar{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right) $ For Balmer series $ {{n}_{1}}=2 $ and for 4th line in Balmer series $ {{n}_{2}}=6 $ $ \because $ $ R=109677\,c{{m}^{-1}} $ $ \bar{v}=109677\left( \frac{1}{4}-\frac{1}{36} \right) $ $ =109677\left( \frac{1}{4}-\frac{1}{36} \right) $ $ \bar{v}=24,372\,c{{m}^{-1}} $