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Chemistry
What is the two third life of a first order reaction having k=5.48× 10-14s-1
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Q. What is the two third life of a first order reaction having $ k=5.48\times 10^{-14}s^{-1} $
J & K CET
J & K CET 2006
Chemical Kinetics
A
$ 2.01\times 10^{11}s $
13%
B
$ 2.01\times 10^{13}s $
55%
C
$ 8.08\times 10^{13}\,s $
20%
D
$ 16.04\times 10^{11}\,s $
13%
Solution:
For two-third of a reaction:
${[A]_{0}=a,[A]=a-\frac{2}{3} a=\frac{a}{3}} $
$t_{2 / 3}=\frac{2.303}{k} \log \frac{[A]_{0}}{[A]}$
$=\frac{2.303}{k} \log \frac{a}{\frac{a}{3}}=\frac{2.303}{k} \log 3 $
$t_{2 / 3}=\frac{2.303 \times 0.4771}{5.48 \times 10^{-14}}$
$=2.01 \times 10^{13} s$