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Q.
What is the solubility product constant for silver phosphate if the solubility of $ A{{g}_{3}}P{{O}_{4}} $ is $ 4.4\times {{10}^{-5}}M $ ?
CMC MedicalCMC Medical 2013
Solution:
For $ A{{g}_{3}}P{{O}_{4}}, $ if s is solubility, then $ {{K}_{sp}}=(3{{s}^{3}})(s)=27{{s}^{4}}=27\,{{(4.4\times {{10}^{-5}})}^{4}} $ $ ={{10}^{-16}} $