Question

What is the sign of $\Delta G^\circ $ and the value of K an electrochemical cell for which $E_{c e l l}^{o}=0.80V$ ?

$\Delta G^\circ $ K

• A. ΔG = -ve
  
  k > 1
• B. ΔG = +ve
  
  k > 1
• C. ΔG = +ve
  
  k < 1
• D. ΔG = -ve
  
  k < 1

Answer 1

Answer: (A)

As $\Delta G^\circ =-nFE_{c e l l}^{o}=-0.8nF$

Hence $\Delta G^\circ =$ negative

$K_{e q}=antilog\left(\frac{- \Delta G ^\circ }{2.303 R T}\right)$

As $\Delta G^\circ $ is negative so $K_{e q}$ will be positive or > 1.