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Q. What is the $S.I$. unit of van der Waals’ constant $'a'$ ?

States of Matter

Solution:

As we know, $P =\frac{an^{2}}{V^{2}}$
$a = \frac{PV^{2}}{n^{2}}$
$= \frac{\left(Pa\right)\left(m^{3}\right)^{2}}{\left(mol\right)^{2}}$
$= Pa\, m^{6}\,$ mol $^{-2}$