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Q. What is the quantity of electricity (in coulombs)required to deposit all the silver from $250 \,mL$ of $1\, M\, AgNO_3$ solution ? ($Ag = 108$)

Electrochemistry

Solution:

Amount of $Ag$ in solution $= M \times V \,(mL)$
$= 1 \times 250 = 250 \,m \,mol$
$= 250 \times 10^{-3}\, mol$
$= 0.25 \,mol$
$\underset{1\,mol}{Ag^+} + \underset{96500\,C}{e^-} \rightarrow Ag$
Reduction of $1 \,mol$ of $Ag$ requires $96500\, C$
Reduction of $0.25 \,mol$ of $Ag$ requires
$= 96500 \times 0.25 = 24125 \,C$