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Q. What is the product obtained in the reaction of $HgCl_2$ and $Hg(CN)_2$?

The p-Block Elements - Part2

Solution:

$\underset{\text{Mercuric chloride}}{HgCl_2} + \underset{\text{Mercuric cyanide }}{Hg(CN)_2} \rightarrow HgCl_2.Hg(CN)_2$