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Mathematics
What is the probability that a non-leap year has 53 Sundays?
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Q. What is the probability that a non-leap year has 53 Sundays?
Probaility
A
$\frac{6}{7}$
B
$\frac{1}{7}$
C
$\frac{5}{7}$
D
$\frac{2}{7}$
Solution:
(i) A non-leap year contains 365 days and there is only one odd day.
(ii) 52 weeks contains 52 Sundays. Find the probability that odd day is Sunday.