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Q. What is the potential energy of the equal positive point charges of $ 1\,\mu C $ each held 1 m apart in air?

AMUAMU 1999

Solution:

: Potential energy $ =\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r} $ $ =(9\times {{10}^{9}})\times \frac{{{10}^{-6}}\times {{10}^{-6}}}{1}J $ $ =9\times {{10}^{-3}}J $