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Q.
What is the potential difference between the points $A$ and $B$ in the circuit diagram shown in figure?
Current Electricity
Solution:
$R_{1}+R_{3}=15 \Omega ; R_{2}+R_{4}=12\, \Omega$
Let $R$ be the equivalent resistance between $A$ and $D$.
$\frac{1}{R}=\frac{1}{15}+\frac{1}{12}$
$R=\frac{15 \times 12}{27}=\frac{20}{3}\, \Omega$
$I=\frac{20}{20 / 3}=3\, A$
$15 I_{1}=12 I_{2}$ or $I_{1}=\frac{4}{5} I_{2}$
$I_{1}+I_{2}=3 A ; I_{1}=\frac{4}{3}\, A ; I_{2}=\frac{5}{3}\, A$
Potential difference between the points $A$ and $B$,
$V_{A}-V_{B}=5 I_{1}=\frac{20}{3} \text { volt }$
