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Q.
What is the $pH$ at equivalence point in the titration of $0.1 M\, CH _{3} COOH$ and $0.1\, M\, NaOH$ ?
$(k_{a}$ for acetic acid is $\left.1.8 \times 10^{-5}\right)$
Equilibrium
Solution:
For weak acid and strong base;
$pH =7+\frac{1}{2} pK _{ a }+\frac{1}{2} \log \,c$
$=7+\frac{4.74}{2}+\frac{1}{2} \log 10^{-1}=8.87$