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  4. What is the percentage hydrolysis of NaCN in N/80 solution,when the dissociation constant for HCN is 1.3 × 10-9 and Kw = 1.0 × 10-14

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Q. What is the percentage hydrolysis of NaCN in N/80 solution,when the dissociation constant for HCN is $1.3 \times 10^{-9}$ and $K_w = 1.0 \times 10^{-14}$

Equilibrium

Solution:

$h=\sqrt{\frac{K_{w}}{K_{a}C}}=\sqrt{\frac{10^{-14}}{1.3\times10^{-9} \left(1 /80\right)}}$
$=\sqrt{\frac{80\times10^{-5}}{1.3}}=\sqrt{\frac{80}{13}\times10^{-4}}$
$=2.48\times10^{-2}$
$=2.48 \%$