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Q. What is the oxidation state of Cr in $ Cr{{O}_{5}} $ ?

JIPMERJIPMER 2001The d-and f-Block Elements

Solution:

In the structure of $CrO _{5}$, it has four $O$ atoms as peroxide which have oxidation number $=-1$ and one $O$ as oxide (double bonded $O$ ) atom with oxidation number $=-2$.
Let the oxidation number of $Cr$ is $x$.
Then, $x+4 \times(-1)+1 \times(-2)=0$
or $x=+6$
The oxidation number of $Cr$ in $CrO _{5}$ is $+6$.

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