Question

What is the order of polarity of the following bond?
(i) $C - H$
(ii) $F - H$
(iii) $Br - H$
(iv) $Na - I$
(v) $K - F$
(vi) $Li - Cl$

• A. $Li - Cl > K - F > F - H > Br - H > C - H > Na - I$
• B. $K-F>L i-C l>F-H>B r-H>N a-I >C - H$
• C. $K - F > F - H > Li - Cl > Br - H > Na - I > C - H$
• D. $K - F > Li - Cl > F - H > Na - I > Br - H >C - H$

Answer 1

Answer: (D)

Higher the value of electronegativity difference, higher will be the polar nature of the compound.