Question

What is the orbital angular momentum of an electron in $‘f’$ orbital ?

• A. $\frac{1.5\,h}{\pi}$
• B. $\frac{\sqrt{6}\,h}{\pi}$
• C. $\frac{\sqrt{3}\,h}{\pi}$
• D. $\frac{\sqrt{3}\,h}{2\pi}$

Answer 1

Answer: (C)

Orbital angular momentum,

$m v r=\frac{h}{2 \pi} \sqrt{l(l+1)}$

For $f$ -orbital, $l=3$

$\therefore $ Orbital angular momentum,

$m v r=\frac{h}{2 \pi} \sqrt{3(3+1)}=\frac{\sqrt{3} h}{\pi}$