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Q. What is the nature of the resulting solution prepared from $100ml$ of $0.2MH_{2}SO_{4}$ added to $100ml$ of $0.2MNaOH.$

NTA AbhyasNTA Abhyas 2022

Solution:

M.eq. of 0.2M $H_{2}SO_{4}=\frac{2 \times 0.2 M}{1000}\times 100=0.04$
$M.eq.of.2MNaOH$ $=\frac{0.2}{1000}\times 100=0.02$
left $\left[\right.H^{+}\left]\right.=0.04-0.02=0.02$ .
Total volume $=200=\frac{. 02}{200}=.0001=10^{- 4}M$
$pH=4$ .