Question

What is the molarity of a solution containing $10\, g$ of $NaOH$ in $500\, mL$ of solution?

• A. $0.25 \,mol\, L^{-1}$
• B. $0.75 \,mol\, L^{-1}$
• C. $0.5 \,mol\, L^{-1}$
• D. $1.25 \,mol\, L^{-1}$

Answer 1

Answer: (C)

No. of moles of $NaOH = \frac{10}{40} = 0.25\,mol$
$M = \frac{0.25 \times 1000}{500} = 0.5\,mol\,L^{-1}$