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  4. What is the maximum wavelength line in the Lyman series of He +ion :-

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Q. What is the maximum wavelength line in the Lyman series of $He ^{+}$ion :-

Solution:

$\frac{1}{\lambda}= R .(2)^{2}\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)=3 R$
$\lambda=\frac{1}{3 R }$