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Q. What is the maximum number of emission lines when the excited electron of a hydrogen atom in $n = 6$ drops to ground state?

Structure of Atom

Solution:

Maximum number of emission lines
$=\frac{n\left(n-1\right)}{2}$
$=\frac{6\left(6-1\right)}{2}$
$=\frac{30}{2}$
$=15$ lines