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Q. What is the mass percentage of carbon tetrachloride if $22\, g$ of benzene is dissolved in $122 \,g$ of carbon tetrachloride?

Solutions

Solution:

Mass of solution = Mass of $C_6H_6 +$ Mass of $CCl_4$
$= 22 + 122 = 144\, g$
Mass $\%$ of $CCl_4 =$ $\frac{122}{144} \times 100 = 84.72\%$