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Q. What is the major product of the following reaction?
Question

NTA AbhyasNTA Abhyas 2020

Solution:

The first step is anti addition of $Br_{2}$ across the double bond.
Solution In the second step, $EtO^{-}$ $\left(\left(nu\right)^{-}\right)$ gets added by $SN^{1}$ mechanism. And $Br^{-}$ from the dashed position acts as the leaving group leads to the formation of a stable benzylic carbocation.
Solution