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Q.
What is the magnitude of total spin value in case of ${ }_{26} Fe ^{3+}$ ion?
Structure of Atom
Solution:
${ }_{26} Fe -[ Ar ] 3 d^{6} 4 s^{2}$
$\Rightarrow Fe ^{3+}-[ Ar ] 3 d^{5}$
Clearly, it has $5$ unpaired electrons; hence,
Total spin $=+\frac{5}{2}$ or $-\frac{5}{2}$