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Q.
What is the magnetic moment of $ Fe^{3+} $ ion in $ [Fe(CN)_6]^{3-} $ ?
AMUAMU 2010Coordination Compounds
Solution:
$Fe^{3+}=[Ar] 3d^{5}$
$(\because CN^{-}$ being a strong field ligand causes pairing)
$\therefore $ Magnetic moment, $\mu = \sqrt{n(n+2)} BM$
(where, $n$ = number of unpaired electrons)
$=\sqrt{1 (1+2)} =\sqrt{3}$
$=1.73\,BM$