Question

What is the linear velocity of a body on the surface of the earth at the equator? Given the radius of the earth is $6400 \, km$ . Period of rotation of the earth = $24 \, hours$ .

• A. $465ms^{- 1}$
• B. $165 \, m \, s^{- 1}$
• C. $665 \, m \, s^{- 1}$
• D. $410 \, m \, s^{- 1}$

Answer 1

Answer: (A)

$\omega =\frac{2 \pi }{2 4 \times 6 0 \times 6 0}=\text{7.26}\times 10^{- 5}rads^{- 1}$
$\textit{v}=\textit{r}\omega =6400\times 10^{3}\times \text{7.26}\times 10^{- 5}=465ms^{- 1}$