Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
What is the hybridization and geometry of the compound XeOF4 ?
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. What is the hybridization and geometry of the compound
X
e
O
F
4
?
J & K CET
J & K CET 2018
Chemical Bonding and Molecular Structure
A
s
p
3
d
2
and octahedral
31%
B
s
p
3
d
and square pyramidal
17%
C
s
p
3
d
and trigonal bipyramidal
14%
D
s
p
3
d
2
and square pyramidal
38%
Solution:
Number of hybrid orbitals
(
X
)
=
1
2
(
V
.
E
.
+
M
.
A
.
−
c
+
a
)
For,
X
e
O
F
4
V
.
E
.
=
8
;
M
.
A
.
(monovalent atoms)
=
4
(
X
)
=
1
2
(
8
+
4
)
⇒
6
i.e.,
s
p
3
d
2
hybridisation
