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Q. What is the formula of a magnetic oxide of cobalt used in recording tapes that crystallises with cobalt atoms occupying one-eighth of the tetrahedral holes and onehalf of the octahedral holes in a closest packed array of oxide ions?

The Solid State

Solution:

Tetrahedral holes $= 8$, Octahedral holes $= 4$
Cobalt atoms $= \frac{8}{8} = 1$
Oxide ions $=\frac{4}{2} = 2$
Thus, formula is $CoO_2$.