Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. What is the escape velocity for a body on the surface of a planet on which the acceleration due to gravity is $(3.1)^2 ms^{-2}$ and whose radius is 8100 km?

KEAMKEAM 2006Gravitation

Solution:

Escape velocity $v_e=\sqrt{2gR}$
Given, $g=(3.1)^2ms^{-2},$
$R = 8100km = 8 1 00 x 10^3 m.$ = $v_e=\sqrt{2\times(3.1)^2\times8100\times10^3}$
$v_e=12.5\times10^3ms^{-1}$
$\Rightarrow v_e=12.5 kms^{-1}$
$\approx\frac{27.9}{\sqrt5}kms^{-1}$