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  4. What is the equivalent weight of NH3 in the given reaction 3CuO+2NH3 → 3Cu+N2+3H2O

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Q. What is the equivalent weight of $NH_{3}$ in the given reaction
$3CuO+2NH_{3} \to 3Cu+N_{2}+3H_{2}O$

Redox Reactions

Solution:

$2N^{3-} \to (N_{2})^{\circ}+6e^{-}$
2 mole of $NH_{3}$ = 1 mole $N_{2}$
Thus equivalents
$2 \times n=1\times6$
$n=6/2 =3$
$\therefore $ Eq. wt. $=\frac{M}{3}=\frac{17}{3}$