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Q.
What is the equivalent resistance of the network shown in figure?
Current Electricity
Solution:
The network consists of four loops connected in series. Each loop consists of two $1 \,\Omega$ resistors in series connected in parallel with two $2\, \Omega$ resistors in series. Thus the effective resistance $R$ of each loop is given by
$\frac{1}{R}=\frac{1}{2}+\frac{1}{4}$
giving $R=(4 / 3) \Omega$.
Therefore, the equivalent resistance of the network = resistance of four loops connected in series, each having an effective resistance of $(4 / 3)\, \Omega=4 \times(4 / 3)=(16 / 3) \,\Omega$
