Q.
What is the equivalent resistance between A and B in given figure?
Solution:
Given circuit is a balanced Wheatstone bridge. So circuit becomes
Equivalent resistance,
$R=\frac{\left(50+50\right)\times\left(50+50\right)}{\left(50+50\right)+\left(50+50\right)}=\frac{100\times100}{200}=50 \Omega$
