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Chemistry
What is the equation for the equilibrium constant (Kc) for the following reaction? (1/2)A(g) + (1/3)B(g) xrightleftharpoonsT(K) (2/3)C(g)
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Q. What is the equation for the equilibrium constant $ (K_{c})$ for the following reaction? $\frac{1}{2}A(g) + \frac{1}{3}B(g)\xrightleftharpoons{T(K) } \frac{2}{3}C(g)$
JIPMER
JIPMER 2009
Equilibrium
A
$K_{c}=\frac{[A]^{1 / 2}[B]^{1 / 3}}{[C]^{3 / 2}}$
1%
B
$K_{c}=\frac{[C]^{3 / 2}}{[A]^{2}[B]^{3}}$
1%
C
$K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}$
95%
D
$K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}+[B]^{1 / 3}}$
2%
Solution:
$\frac{1}{2}A(g) + \frac{1}{3}B(g)\xrightleftharpoons{T(K)} \frac{2}{3}C(g)$
Equilibrium constant, $K_{c}=\frac{\text { Rate product }}{\text { Rate of reactant }}$
$K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}$