Question

What is the equation for the equilibrium constant $\left(K_{c}\right)$ for the following reaction?
$\frac{1}{2} A(g)+\frac{1}{3} B(g) \ce{<=>[T(K)]} \frac{2}{3} C(g)$

• A. $K_{c}=\frac{[A]^{1 / 2}[B]^{1 / 3}}{[C]^{3 / 2}}$
• B. $K_{c}=\frac{[C]^{3 / 2}}{[A]^{2}[B]^{3}}$
• C. $K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}$
• D. $K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}+[B]^{1 / 3}}$

Answer 1

Answer: (C)

$\frac{1}{2} A(g)+\frac{1}{3} B(g) \ce{<=>[T(K)]} \frac{2}{3} C(g)$
Equilibrium constant
$K_{c}=\frac{\text { rate of product }}{\text { rate of reactant }}$
$K_{c}=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}$