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Q.
What is the energy stored in a $50\, mH$ inductor carrying a current of $4A$?
Jharkhand CECEJharkhand CECE 2004
Solution:
Energy stored in an inductor is given by
$E=\frac{1}{2} L i^{2}$
Given, $L=50 \,m H$
$=50 \times 10^{-3} H, i=4 \,A $
$\therefore E=\frac{1}{2} \times 50 \times 10^{-3} \times(4)^{2} $
$\Rightarrow E=0.4 \,J$