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Q. What is the energy required to move the electron from ground state of $H$ atom to the first excited state? Given that the ground state energy of $H$ atom is $13.6\, eV$ and that the energy $E_{n}$ of an electron in $n$ th orbital of an atom or ion of atomic number $Z$ is given by the equation
$E_{n}=-\left(13.6 Z^{2} /n^{2}\right)$.

UPSEEUPSEE 2011Structure of Atom

Solution:

$E_{n}=-\frac{13.6}{n^{2}} Z^{2}$

The energy required to move the electron from ground state $(n=1)$ of $H$ to first excited state $(n=2)$ is

$\Delta E =E_{2}-E_{1}=-13.6\left(\frac{1}{2^{2}}-\frac{1}{1^{2}}\right) $

$=13.6 \times \frac{3}{4}=10.2$ eV