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Q. What is the empirical formula of vanadium oxide if 2.74 g of metal oxide contains 1.53 g of metal?

CMC MedicalCMC Medical 2010

Solution:

Percentage of $ V=\frac{1.53}{2.74}\times 100=55.83 $ $ \therefore $ of $ O=44.17 $
Element
Percentage
Atomic ratio
Simplest ratio
V
55.83
$ \frac{55.83}{52}=1.1 $
$ \frac{1.1}{1.1}=1 $
O
44.17
$ \frac{44.17}{16}=2.76 $
$ \frac{2.76}{1.1}=2.5 $
$ V:O=2:5 $ Thus, empirical formula $ ={{V}_{2}}{{O}_{5}} $