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Q. What is the empirical formula of the compound which has the following percentage composition $C = 80\%, H = 20\%$?

Solution:

$\begin{matrix}C&H\\ 80\%&20\%\end{matrix}$
Moles $\to$ $\begin{matrix}\frac{80}{12}&\frac{20}{1}\\ 6.66&20\end{matrix}$
Moles ratio $\to$ $\begin{matrix}\frac{6.66}{6.66}&\frac{20}{6.66}\\ 1&3\end{matrix}$
$\therefore $ Empirical Formula $\Rightarrow CH_{3}$