Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. What is the EAN of nickel in $ Ni{{(CO)}_{4}} $ ?

Delhi UMET/DPMTDelhi UMET/DPMT 2003

Solution:

EAN = Ac. no. of central metal atom oxidation state of central metal atom + electrons gained from ligands
Atomic no. of $Ni = 28$ Oxidation state of $Ni$ in $ [Ni{{(CO)}_{4}}]=0 $
( $ \because $ Oxidation state of metal in carbonyl is zero)
Electrons gained from ligands $ =2\times 4=8 $
( $ \because $ One ligand donates two electrons to metal atom.)
$ \therefore $ $ EAN=28-0+8=36 $