Q. What is the dimension of velocity gradient?
NTA AbhyasNTA Abhyas 2022
Solution:
Velocity gradient $=\frac{d v}{d y}$
Where $dv$ is the change in velocities of two layers of liquid separated by depth $dy$ .
So $\left[\frac{d v}{d y}\right]=\frac{L T^{- 1}}{L}=T^{- 1}$
Where $dv$ is the change in velocities of two layers of liquid separated by depth $dy$ .
So $\left[\frac{d v}{d y}\right]=\frac{L T^{- 1}}{L}=T^{- 1}$