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Q. What is the dimension of the coefficient of viscosity $\eta$ ?

NTA AbhyasNTA Abhyas 2022

Solution:

Viscous force, $F = 6 \pi \eta \text{r} \nu$
$\therefore \eta=\frac{F }{6 \pi \text{r} \nu}$ $\left[\right. \eta \left]\right. = \frac{\left[\right. F \left]\right.}{\left[\right. \text{r} \left]\right. \left[\right. \nu \left]\right.}$
or $[\eta\left]\right.=\frac{\left[\right. MLT^{- 2} \left]\right.}{\left[\right. L \left]\right. \left[\right. LT^{- 1} \left]\right.}$