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Q.
What is the correct order of bond strength for $ NO, NO^+ $ and $ NO^- $ ?
J & K CETJ & K CET 2017Chemical Bonding and Molecular Structure
Solution:
Electronic configuration of $NO, NO^{+}$ and $NO^{-}:$
NO : $KK{\sigma}2s^{2}{\sigma}^{*}2s^{2}{\sigma}2p^{2}_{z} \pi 2p^{2}_{x}\, \pi 2p^{2}_{y}\pi^{*}2p^{1}_{x}$
$NO^{+}: KK{\sigma}2s^{2}{\sigma}^{*} 2s^{2}{\sigma} 2p^{2}_{z} \pi 2p^{2}_{x} \pi 2 p^{2}_{y}$
$NO^{-}: KK{\sigma}\, 2s^{2} {\sigma}^{*} 2s^{2}{\sigma}2p^{2}_{z}\pi 2p^{2}_{x} \pi 2p^{2}_{y} \pi^{*} 2 p^{1}_{x}$
$= \pi^{*} 2p^{1}_{y}$
Bond order $=\frac{1}{2} (N_{b}-N_{a})$
B.O. of NO $=\frac{1}{2} (8-3)=2.5$
B.O. of $NO^{+}=\frac{1}{2}(8-2)=3$
B.O. of $NO^{-}=\frac{1}{2}(8-4)=2$
Bond strength $\propto$ Bond order Thus order of bond strength is :
$NO^{+} > \, NO >\, NO^{-}$