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  4. What is the correct orbital designation of an electron with the quantum number, n=4,l=3,m=-2,s=(1/2)?

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Q. What is the correct orbital designation of an electron with the quantum number,
$n=4,l=3,m=-2,s=\frac{1}{2}? $

Bihar CECEBihar CECE 2010Structure of Atom

Solution:

The value of n decides the shell of electrons.
The value of $ l $ decides the orbital; $ l=0 $ is $ s,l=1 $ is d and $ l=3 $ is $ f $
Given, $ n=4,l=3,m=-2,s=-\frac{1}{2} $
$ \therefore $ It is $ 4f $ orbital.