Question

What is the correct explanation of the non-reducing property of sucrose ?

• A. $ \alpha $ - $ D $ -glucopyranose and $ \beta $ - $ D $ -fructofuranose are linked via $ C_2 $ and $ C_1 $ centres respectively
• B. $ \alpha $ - $ D $ -glucopyranose and $ \beta $ - $ D $ -fructofuranose are linked via $ C_1 $ and $ C_2 $ centres respectively
• C. $ \alpha $ - $ D $ -glucopyranose and $ \beta $ - $ D $ -fructofuranose are linked via $ C_2 $ and $ C_2 $ centres respectively
• D. $ \alpha $ - $ D $ -glucopyranose and $ \beta $ - $ D $ -fructofuranose are linked via $ C_3 $ and $ C_4 $ centres respectively

Answer 1

Answer: (B)

Sucrose is a non-reducing sugar since, both glucose $(C_{1}-{\alpha})$ and fructose $(C_{2}-\beta)$ are connected to each other through their reducing centres.