Question

What is the correct explanation of the non-reducing property of sucrose?

• A. $\alpha $ -D-glucopyranose and $\beta $ -D-fructofuranose are linked via $C_{2}$ and $C_{1}$ centres respectively
• B. $\alpha $ -D-glucopyranose and $\beta $ -D-fructofuranose are linked via $C_{1}$ and $C_{2}$ centres respectively
• C. $\alpha $ -D-glucopyranose and $\beta $ -D-fructofuranose are linked via $C_{2}$ and $C_{2}$ centres respectively
• D. $\alpha $ -D-glucopyranose and $\beta $ -D-fructofuranose are linked via $C_{3}$ and $C_{4}$ centres respectively

Answer 1

Answer: (B)

Sucrose is a non-reducing sugar since, both glucose $\left(\right.C_{1}-\alpha \left.\right)$ and fructose $\left(\right.C_{1}-\beta \left.\right)$ are connected to each other through their reducing centers.