Question

What is the correct dipole moment of $NH_{3}$ and $NF_{3}$ respectively?

• A. $4.90\times10^{-30} C m$ and $0.80 \times10^{-30} C m$
• B. $0.80\times10^{-30} C m$ and $4.90 \times10^{-30} C m$
• C. $4.90\times10^{-30} C m$ and $4.90 \times10^{-30} C m$
• D. $0.80\times10^{-30} C m$ and $0.80 \times10^{-30} C m$

Answer 1

Answer: (A)

1Debye $=10^{-18}$ esucm
As shown in the image all the vectors in $NH _{3}$ are in the same direction and in opposite direction in the case of $NF _{3}$.
so the resultant dipole moment will be more for $NH _{3}$.