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  4. What is the change in oxidation number of carbon in the following reaction ? CH4(g) + 4Cl2 (g) arrow CCl4(l) + 4HCl (g)

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Q. What is the change in oxidation number of carbon in the following reaction ?
$CH_4(g) + 4Cl_2 (g) \rightarrow CCl_4(l) + 4HCl (g)$

NEETNEET 2020Redox Reactions

Solution:

Oxidation number of $C$ in $CH_4$ is $- 4$
as $x + 4 = 0$$\,\, x = - 4 (x$ is oxidation state of carbon)
oxidation of $C$ in $CCl_4$ is $+ 4$
as $x - 4 = 0 \,\,\,x = + 4$
$\therefore $ Change in oxidation state of carbon is from $-4$ to $+4$