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Q.
What is the area of the plates of a 3F parallel plate capacitor, if the separation between the plates is 5 mm ?
Electrostatic Potential and Capacitance
Solution:
The expression of parallel plate capacitor is given by
$C =\frac{ A \epsilon_{0}}{ d }$ so area of plate,
$A=\frac{C d}{\epsilon_{0}}=\frac{3 \times\left(5 \times 10^{-3}\right)}{8.85 \times 10^{-12}}$
$=1.694 \times 10^{9} m ^{2}$