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Q. What is the amount of energy released by deuterium and tritium fusion?

AIIMSAIIMS 2007Nuclei

Solution:

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The energy released in the process is given by
$Q=\left[M_{_{^{2}_{1}H}}+M_{_{^{3}_{1}H}}-M_{_{^{4}_{2}He}}-M_{_{^{1}_{0}n}}\right]c^{2}$
$=\left[2.014102 + 3.016050 - 4.002603- 1.008665\right]uc^{2}$
$=\left(0.018884\,u\right)\left[931.5 \frac{MeV}{u}\right]=17.6\,MeV.$