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Q. What is $pOH$ of an aqueous solution with hydrogen ion concentration equal to $3 \times 10^{-5}\,mol\, L^{-1}$?

Equilibrium

Solution:

$pH = -log[H^+]$
$= -log(3 \times 10^{-5}) $
$= 4.5229$
$pOH = 14 - pH$,
$14 - 4.5229 = 9.47$